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Example   2






                                                      dy
               Solve the differential equation           +  y =  sin  t 3 , given that y=0 when t=0
                                                      dt
                STEP 1: Take the Laplace Transform for both sides.

                               '
                           L [ ] yty )( +  =  [ L sin  ] t 3


                STEP 2: Substitude the theorem for Left Hand Side (LHS) .

                           Find the Laplace for Right Hand Side (RHS)
                                                3
                          [sY (s ) −  ) 0 ( y  + y ] =
                                              s 2  + 9

                STEP 3 : Substitude the values of y(0)=1, t=0
                                             3
                          [sY (s ) − 0 + y ] =
                                           s 2  +  9
                STEP 4 : Solve for Y(s)
                                           3
                           [sY (s ) + y ] =
                                         s 2  +  9
                                           3
                            Y (s )[ +  ] 1 =
                                 s
                                         s 2  + 9
                                               3
                                  Y (s ) =       2
                                          s
                                         ( + 1 )(s  +  ) 9
                STEP 5 : Solve for the inverse ,     (    ) =        −     [    (    )] using Partial Fraction.
                                            3       
                             y  ) (t  = L −1   2    
                                         (s  + )(1 s  + )9  
                                   3       =   A  +  Bs  + C
                             ( +s  1 )(s 2  +  ) 9  s  + 1  (s 2  +  ) 9

                                       3 = A (s 2  +  ) 9 +  (Bs  + C )( +s  ) 1  ………………equation 1
                if s= -1
                                       2
                             3 = A ((−  ) 1 + 9
                             3 =  ( A 10 )

                                  3
                               =
                             A
                                 10









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