Page 36 - LAPLACE TRANSFORM
P. 36

Example   6








                 By using the First Shifting Theorem determine the Laplace Transforms.

                  f  ) (t =  L {e 3t  cos 2  2t }



                                                        1       s
                      we know that :-  {cos      2 2t } =  +
                                           L
                                                        2s     2s 2  + 32
                                                      1       s
                                         L {cos 2  2t } =  +
                                                     2s   2s 2  + 32
                                                           1         ( −   ) 2
                                                                      s
                                         L {e 2t  cos 2  2t } =     +
                                                          s
                                                                    s
                                                                         2
                                                         ( 2 −  ) 2  ( 2 −  ) 2 + 32
                                                                       s
                                                           1          ( −   ) 2
                                                      =        +
                                                                   s
                                                         2 − 4    ( 2 − 2 s  ) 2 + 32
                                                                       )( −
                                                          s
                                                                         s
                                                          1             ( −  ) 2
                                                      =  2 − 4  +  ( 2 s 2  − 2 − ss  2 +  ) 4 + 32
                                                         s
                                                                       s
                                                          1           ( −  ) 2
                                                      =       +
                                                                      4 +
                                                        2 − 4    ( 2 s 2  − s  ) 4 + 32
                                                         s
                                                                     s
                                                          1         ( −   ) 2
                                                      =       +
                                                                     8 +
                                                        2 − 4   2s 2  − s  8+ 32
                                                         s
                                                                    s
                                                          1        ( −  ) 2
                                                      =       +
                                                                     8 +
                                                         s
                                                        2 − 4   2s 2  − s  40














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